Czech Republic’s Maria Bouzkova has broken new ground at Wimbledon by reaching the quarter-finals on Sunday.
Coming into the tournament, the 23-year-old has failed to win back-to-back matches in 12 Grand Slam appearances. However, the past week has seen her breakthrough with a surprise run to the quarter-finals. She secured a place in the last eight with a 7-5, 6-2, win over France’s Caroline Garcia. The player who defeated Emma Raducanu in the second round.
In her latest match, Bouzkova was by far the most consistent player on the court as she produced just four unforced errors against 13 winners. In comparison, Garcia’s tally was 25 against 24. She broke the Frenchwoman four times in the match en route to victory.
“I don’t know how I got here,” said Bouzkova.
“Now we will celebrate with strawberries and cream. It’s one of our 100 routines at Wimbledon.”
Bouzkova’s run at Wimbledon has brought the Czech into the limelight for the first time. Although some may not be too familiar with the right-hander who plays with a two-handed backhand. Here are five things to know about the underdog.
- As a junior, she won the 2014 US Open title and reached the final of the Wimbledon doubles event that same year.
- Wimbledon is where Bouzkova won her first Grand Slam main draw match back in 2019 after defeating Mona Barthel in the first round.
- Prior to Garcia, she defeated Danielle Collins, Ann Li and Alison Riske-Amritraj this week. Collins was the sixth top 20 player she has defeated and second this year after Karolina Pliskova.
- She was ranked as low as 97th in the world earlier this season but is currently up to 66. Her career-best is 46.
- Has reached three WTA finals in as many years in Guadalajara (2022), Melbourne 250 (2021) and Monterey (2020).
- She has a win-loss record of 18-9 so far this season. Although prior to Wimbledon, she has not won any matches on the grass after losing in the first round of Eastbourne to Shelby Rogers.
Bouzkova will play either second seed Ons Jabeur or Elise Mertens in the quarter-finals.